Question

mình không hiểu dạng này lắm nên mong mn chỉ bảo

Answer 1

\(A=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2}{x-\sqrt{x}}\right):\dfrac{1}{\sqrt{x}-1}\\ =\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2}{\sqrt{x}\left(\sqrt{x}-1\right)}\right):\dfrac{1}{\sqrt{x}-1}\\ =\left(\dfrac{\sqrt{x}.\sqrt{x}+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\right)\times\dfrac{\sqrt{x}-1}{1}\\ =\dfrac{x+2}{\sqrt{x}\left(\sqrt{x}-1\right)}\times\dfrac{\sqrt{x}-1}{1}\\ =\dfrac{x+2}{\sqrt{x}}\)