Question

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Answer 1

\(\left\{{}\begin{matrix}3\left(x+1\right)+2y=23\\x+4\left(y-2\right)=2\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}3x+3+2y=23\\x+4y-8=2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}3x+2y=20\\x+4y=10\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}-6x-4y=-40\\x+4y=10\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}-5x=-30\\x+4y=10\end{matrix}\right.\)  \(\Leftrightarrow\left\{{}\begin{matrix}x=6\\y=\dfrac{10-x}{4}=1\end{matrix}\right.\)