Bài 1:
a. \(R=R1+R2=20+40=60\Omega\)
b. \(I=I1=I2=\dfrac{U}{R}=\dfrac{24}{60}=0,4A\left(R1ntR2\right)\)
Bài 3:
\(P_2>P_1\left(40>10\right)\Rightarrow\) đèn 2 sáng hơn.
Bài 2:
a. \(U_b=U-U_d=12-9=3V\)
\(I=I_d=I_b=0,5A\left(R_dntR_b\right)\)
\(\Rightarrow R_b=U_b:I_b=3:0,5=6\Omega\)
b. \(R=p\dfrac{l}{S}\Rightarrow l=\dfrac{R.S}{p}=\dfrac{20\cdot0,5\cdot10^{-6}}{1,1\cdot10^{-6}}\approx9,1\left(m\right)\)