Question

\(\left\{x+\frac{1}{5}\right\}^2+\frac{17}{25}=\frac{26}{25}\)

Answer 1

=7/25

Answer 2

Ta có: \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

<=> \(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}=\frac{9}{25}\)

<=> \(x+\frac{1}{5}=\frac{9}{25}\)và \(x+\frac{1}{5}=-\frac{9}{25}\)

=> x= \(\frac{4}{25}\) và x=\(-\frac{14}{25}\)

Answer 3

Ta có:

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)

\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)

\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\)

\(\Rightarrow x=\frac{3}{5}-\frac{1}{5}=\frac{2}{5}\)

Vậy giá trị của x là \(\frac{2}{5}\)
 

Answer 4

\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\Rightarrow TH.1\)                                                            \(TH.2\)

\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)                                     \(\left(x+\frac{1}{5}\right)^2=\left(\frac{-3}{5}\right)^2\)

\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\)                                               \(\Rightarrow x+\frac{1}{5}=\frac{-3}{5}\)

\(x=\frac{3}{5}-\frac{1}{5}\)                                                        \(x=\frac{-3}{5}-\frac{1}{5}\)

\(x=\frac{2}{5}\)                                                                    \(x=\frac{-4}{5}\)

                       Vậy x = \(\frac{2}{5}\) hoăc x =    \(\frac{-4}{5}\)

Chúc bạn zui ~^^

Answer 5

\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)

\(\left(x+\frac{1}{5}\right)^2=\frac{3}{5}^2\)
\(x+\frac{1}{5}=\frac{3}{5}\)
\(x=\frac{2}{5}\)