\(\left|x+\frac{1}{2}\right|-\frac{2}{3}=\sqrt{\frac{16}{9}}\)
\(\left|x+\frac{1}{2}\right|-\frac{2}{3}=\frac{4}{3}\)
\(\left|x+\frac{1}{2}\right|=\frac{4}{3}+\frac{2}{3}\)
\(\left|x+\frac{1}{2}\right|=2\)
TH1: \(x+\frac{1}{2}=2\)
\(x=2-\frac{1}{2}\)
\(x=\frac{3}{2}\)
TH2: \(x+\frac{1}{2}=-2\)
\(x=-2-\frac{1}{2}\)
\(x=\frac{-5}{2}\)
KL: x =3/2 hoặc x= -5/2
\(\left|x+\frac{1}{2}\right|-\frac{2}{3}=\sqrt{\frac{16}{9}}\)
\(\Leftrightarrow\left|x+\frac{1}{2}\right|-\frac{2}{3}=\frac{4}{3}\)
\(\Leftrightarrow\left|x+\frac{1}{2}\right|=\frac{8}{3}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{2}=\frac{8}{3}\\x+\frac{1}{2}=-\frac{8}{3}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{13}{6}\\x=-\frac{19}{6}\end{cases}}\)
vậy.....
\(\left|x+\frac{1}{2}\right|-\frac{2}{3}=\sqrt{\frac{16}{9}}\)
\(\Rightarrow\left|x+\frac{1}{2}\right|-\frac{2}{3}=\frac{4}{3}\)
\(\Rightarrow\left|x+\frac{1}{2}\right|=\frac{4}{3}+\frac{2}{3}\)
\(\Rightarrow\left|x+\frac{1}{2}\right|=\frac{6}{3}\)
\(\Rightarrow\left|x+\frac{1}{2}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{2}=2\\x+\frac{1}{2}=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{5}{2}\end{cases}}}\)
Vậy \(\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{5}{2}\end{cases}}\)
~ Ủng hộ nhé