\(\left(x+5\right)^3=64\)
\(\left(x+5\right)^3=4^3\)
\(\Rightarrow x+5=4\)
\(x=4-5\)
\(x=-1\)
\(\left(2x-3\right)^2=9\)
\(\left(2x-3\right)^2=3^2\)
\(\Rightarrow2x-3=3\)
\(\Rightarrow2x=3+3\)
\(2x=6\)
\(x=6:2\)
\(x=3\)
đúng nha thanhthaowinx
a)ta có: \(\left(x+5\right)^3=64\)
=> \(\left(x+5\right)^3=\left(4\right)^3\)
=> \(x+5=4\)
<=>\(x=4-5=-1\)
b)Lại có: \(\left(2x-3\right)^2=9\)
=>\(\left(2x-3\right)=\left(+-3\right)^2\)
=>\(2x-3=3\) hoặc \(2x-3=-3\)
<=> 2x= 0 hoặc 2x= -6
<=> x= 0 hoặc x= -3
Vậy \(x\in \left\{0;-3\right\}\)
