(x + 1)(x + 2)(x + 3)(x + 4) - 24 = 0
=> (x + 1)(x + 2)(x + 3)(x + 4) = 0 + 24 = 24
=> (x + x + x + x)(1 + 2 + 3 + 4) = 24
=> 4x . 10 = 24
=> 4x = 24 : 10 = 2,4
=> x = 2,4 : 4 = 0,6
Vậy x = 0,6
giải theo cahcs của Võ Thị Mỹ Duyên đc k z
(x + 1)(x + 2)(x + 3)(x + 4) - 24 = 0
=> (x + 1)(x + 2)(x + 3)(x + 4) = 0 + 24 = 24
=> (x + x + x + x)(1 + 2 + 3 + 4) = 24
=> 4x . 10 = 24
=> 4x = 24 : 10 = 2,4
=> x = 2,4 : 4 = 0,6
Vậy x = 0,6
giải theo cahcs của Võ Thị Mỹ Duyên đc k z
Jup Gin ik mak TvT
1,\(\left(x+1\right)^3+\left(x-2\right)^3=\left(2x-1\right)^3\)
2,\(\left(x+1\right)^4+\left(x+3\right)^4=82\)
3,\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24=0\)
4,\(\left(x^2-3x+2\right)\left(x^2+15x+56\right)+8=0\)
Tìm \(x\):
\(8\)) \(1-\left(x-6\right)=4\left(2-2x\right)\)
\(9\))\(\left(3x-2\right)\left(x+5\right)=0\)
\(10\))\(\left(x+3\right)\left(x^2+2\right)=0\)
\(11\))\(\left(5x-1\right)\left(x^2-9\right)=0\)
\(12\))\(x\left(x-3\right)+3\left(x-3\right)=0\)
\(13\))\(x\left(x-5\right)-4x+20=0\)
\(14\))\(x^2+4x-5=0\)
Giải phương trình\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24=0\)
giải phương trình
A/\(\left(x^2+x\right)^2-\left(x^2+x\right)-2=0\)
B/\(\left(x^2+3x\right)^2+4\left(x^2+3x\right)=12\)
C/\(\left(x^2+x-2\right)\left(x^2+x-3\right)=12\)
D/\(x\left(x+1\right)\left(x+2\right)\left(x+3\right)+1=0\)
E/\(x\left(x-1\right)\left(x+1\right)\left(x+2\right)-24=0\)
F/\(\left(x+2\right)^2\left(2x+1\right)\left(2x+3\right)=18\)
\(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)-24=0\)tìm x
1) \(\left(3-x^2\right)+6-2x=0\)
2) \(5\left(2x-1\right)+7=4\left(2-x\right)+2\)
3) \(x^2-6x+4\left(x-6\right)=0\)
4) \(\left(x+1\right)\left(2x-3\right)=x\left(x+1\right)\)
Giải các PT sau
a)\(\left(3\left(x+1\right)-2\left(x+3\right)\right)^3+\left(2\left(x+3\right)-x+5\right)^3+\left(x-5-3\left(x+1\right)\right)^3=0\)
b)\(\left(x-2\right)^3+\left(x-4\right)^3+\left(x-7\right)^3+3\left(x-2\right)\left(x-4\right)\left(x-7\right)=0\)
Bài Tập: Giải phương trình :
a) (x + 5)(2x - 3) = 0
b) \(\left(x^2-9\right)\left(4-x\right)=0\)
c) \(\left(2x+3\right)\left(4-5x\right)=0\)
d) \(2\left(x+3\right)\left(x-4\right)=0\)
e) \(\left(x^2-9\right)\left(4-x\right)=0\)
f) \(\left(2x+3\right)\left(x^2-16\right)=0\)
a \(\left(x^2+3x+2\right).\left(x^2+3x+3\right)-2=0\)
b \(\left(x+1\right).\left(x+2\right).\left(x+3\right).\left(x+4\right)-24=0\)
c \(x^3+3x^2+3x=7\)