=> x + 1 + x + 2 + ... + x + 100 = 5750
=> ( x + x + ... + x ) + ( 1 + 2 + .... + 100 ) = 5750
=> 100x + 5050 = 5750
=> 100x = 5750 - 5050
=> 100x = 700
=> x = 7 00 : 100
=> x = 7
x + x + x + x + ....+x +x + 1 + 2 + 3 + .... + 100 = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
tìm x \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+\left(x+4\right)+...+\left(x+99\right)+\left(x+100\right)=5750\)
\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
a) \(A=4+2^2+2^3+...+2^{20}\)
b) Tìm x, biết : \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
Tim \(x\in Z\), biet rang :
a) \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
b) \(\left(x+2\right)+\left(4x+4\right)+\left(7x+6\right)+...+\left(25x+28\right)+\left(28x+20\right)=1560\)
\(\left|x+y+\frac{1}{100}\right|\)\(=-\left|x\right|-\left|y\right|-\left|\frac{1}{10}\right|\)
\(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|+...+\left|x+200\right|=201\)
Tìm x
a) \(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+.....+\left(x-100\right)=101\)
b) \(x+2x+3x+....+100x=1000\)
c) \(x+1+2\left(x+2\right)+3\left(x+3\right)+...+100\left(x+100\right)=101^2\)
d) \(\frac{1+x}{1}+\frac{1+x}{2}+\frac{1+x}{3}+...+\frac{1+x}{30}=0\)
e) \(\left(1+\frac{x}{1}\right)\left(2-\frac{x}{2}\right)\left(3-\frac{x}{3}\right)=0\)
BẠN NÀO BIẾT PHẦN NÀO THÌ GIÚP MIK NHÉ!
Thank!!
\(\left\{x+1\right\}+\left\{x+2\right\}\left\{x+3\right\}+....+\left\{x+100\right\}=5550\)
1, Tính \(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)2,Tính \(\left(1-\frac{1}{2^2}\right)x\left(1-\frac{1}{3^2}\right)x\left(1-\frac{1}{4^2}\right)x...x\left(1-\frac{1}{n^2}\right)\)
Tìm x biết:\(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|+...+\left|x+100\right|=605x\)
