Question

\(\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\left(x^4+x^4\right)\left(x^8+y^8\right)\)

rút gọn biểu thức

 

Answer 1

=(x^2-y^2)(X^2+y^2)(X^4+y^4)(x^8+y^8)

=(x^4-y^4)(x^4+y^4)(x^8+y^8)

=(x^8-y^8)(x^8+y^8)

=x^16 - y^ 16

IF you can , give my answer a k

Answer 2

Bạn áp dụng hằng đẳng thức x² - y² = (x-y)(x+y) 

\(\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\left(x^4+y^4\right)\left(x^8+y^8\right)\)

\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\left(x^4+y^4\right)\left(x^8+y^8\right)\)

\(=\left(x^4-y^4\right)\left(x^4+y^4\right)\left(x^8+y^8\right)\)

\(=\left(x^8-y^8\right)\left(x^8+y^8\right)=x^{16}-y^{16}\)

Answer 3

(x-y)(x+y)(x²+y²)(x⁴+y⁴)(x⁸+y⁸)

= (x²-y²)(x²+y²)(x⁴+y⁴)(x⁸+y⁸)

= (x⁴-y⁴)(x⁴+y⁴)(x⁸+y⁸)

= (x⁸-y⁸)(x⁸+y⁸)

= (x¹⁶-y¹⁶)

#Ttt