\(\left(x-\frac{1}{2}\right)^5+\left(y+\frac{1}{3}\right)^3=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=0\\y+\frac{1}{3}=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0+\frac{1}{2}\\y=0-\frac{1}{3}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\y=-\frac{1}{3}\end{cases}}\)
Vậy \(\left(x;y\right)\in\left(\frac{1}{2};-\frac{1}{3}\right)\)