<=> có 2 trường hợp
T1: x - 3 = 0
=> x = 0+3=3
T2: x - 4 = 0
=> x=0+4=4
=> x-3 = 0 x-4 = 0
* x = 0+3 *x = 0+4
=> x = 3 hoặc x = 4
Tìm các số nguyên x thỏa mãn :
a, \(\left(x-2\right)\left(x-7\right)< 0\)
b, \(\left(x^2-3\right)\left(x^2-10\right)< 0\)
c, \(\left(x^2-1\right)\left(x^2-4\right)\left(x^2-7\right)\left(x^2-10\right)< 0\)
d, \(\left(x^3+5\right)\left(x^3+10\right)\left(x^3+15\right)\left(x^3+30\right)< 0\)
a) \(\left(x^2-5\right).\left(x^2-25\right)< 0\)
b) \(\left(x+5\right).\left(9+x^2\right)< 0\)
c) \(\left(x+3\right).\left(x^2+1\right)=0\)
d) \(\left(x+5\right).\left(x^2-4\right)=0\)
\(\left(x-1\right)\left(x+1\right)+2=0\)
\(\left(x+1\right).\left(3-x\right)=0\)
\(\left(2-x\right)^4=81\)
\(\left(x^2+1\right).\left(81-x^2\right)=0\)
Tìm x \(\in\)Z , biết:
a)(\(\left(x-4\right).\left(x+7\right)=0\)
b)\(x.\left(x+3\right)=0\)
c)\(\left(x-2\right).\left(5-x\right)=0\)
d)\(\left(x-1\right).\left(x^2+1\right)=0\)
Tìm x, biết :
a) \(\left(\frac{3}{4}.x-\frac{9}{16}\right).\left(\frac{1}{3}+\frac{-3}{5}:x\right)=0\)
b) \(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
c) \(\left(x+\frac{3}{5}\right).\left(x+1\right)< 0\)
Tìm x, biết :
a) \(\left(\frac{3}{4}.x-\frac{9}{16}\right).\left(\frac{1}{3}+\frac{-3}{5}:x\right)=0\)
b) \(\left(x-\frac{1}{3}\right).\left(x+\frac{2}{5}\right)>0\)
c) \(\left(x+\frac{3}{5}\right).\left(x+1\right)< 0\)
tìm x
\(\frac{\left(x+1\right)}{15}+\frac{\left(x+2\right)}{14}+\frac{\left(x+3\right)}{13}+\frac{\left(x+4\right)}{12}+\left(x+20\right)=0\)
\(\left(4\frac{1}{6}x^2-\frac{2}{3}\right)\left(-0,75x-\frac{21}{32}\right)\left(\frac{5}{6}\left|x\right|-3\frac{1}{3}\right)\)\(\left(4\frac{1}{2}x^4+1\frac{1}{3}x\right)=0\)
\(\left(4\frac{1}{6}x^2-\frac{2}{3}\right)\left(-0,75x-\frac{21}{32}\right)\left(\frac{5}{6}\left|x\right|-3\frac{1}{3}\right)\)\(\left(4\frac{1}{2}x^4+1\frac{1}{3}x\right)=0\)
\(\left(x^2+5\right).\left(x-3\right)>0\)
\(\left(-x^2-7\right).\left(x+10\right)>0\)
\(\left(x-2\right).\left(x+2\right)< 0\)
\(\left(x-2\right)^2-25=0\)
\(\left(x^2+1\right).\left(x-2\right).\left(x+3\right)>0\)
