Question

\(\)\(\left(x-3\right).\left(x-2\right)-\left(x+1\right).\left(x-5\right)=0\)
bài tìm x ạ

Answer 1

\(x^2-3x-2x+6-\left(x^2+x-5x-5\right)=0\\ x^2-5x+6-x^2+4x+5=0\\ -x+11=0\\ -x=-11\\ x=11\)

Answer 2

\(\left(x-3\right).\left(x-2\right)-\left(x+1\right).\left(x-5\right)=0\)

`<=>x^2-2x-3x+6-x^2+5x-x+5=0`

`<=>-x+11=0`

<=>x=11`

Answer 3

\(\left(x-3\right).\left(x-2\right)-\left(x+1\right).\left(x-5\right)=0\)

`x^2 -5x+6 - x^2 +4x+5=0`

`(x^2-x^2)+(-5x+4x)+(6+5)=0`

`-x+11=0`

`-x=-11`

`=> x = 11`