( x - 1 )5 = 32
( x - 1 )5 = 25
x - 1 = 2
x = 2 + 1
x = 3
nha bn mik nhanh nhất
ai trả lời giúp mình nhanh nhất sẽ được hihi
\(\left(x-1\right)^5=32\Rightarrow\left(x-1\right)^5=2^5\Rightarrow x-1=2\Rightarrow x=3\)
( x - 1 )5 = 32
( x - 1 )5 = 25
x - 1 = 2
x = 2 + 1
x = 3
nha bn mik nhanh nhất
ai trả lời giúp mình nhanh nhất sẽ được hihi
\(\left(x-1\right)^5=32\Rightarrow\left(x-1\right)^5=2^5\Rightarrow x-1=2\Rightarrow x=3\)
\(x^2-19=5.9;\left(2x+1\right)^3=-0,001;\left(\dfrac{5}{6}\right)^{2x-1}=\left(\dfrac{5}{6}\right)^5;\left(\dfrac{1}{3}x-\dfrac{2}{3}\right)^3=27;\left(\dfrac{1}{32}\right)^x=\left(\dfrac{1}{2}\right)^{15}\)
a)\(\left(\frac{1}{2}\right)^{2\times x+1}=\frac{1}{32}\)
b)\(\left|5-x\right|+\left|x-3\right|=0\)
c)\(\left(x+1\right)\left(x-3\right)< 0\)
1. Tính:
a)\(81^3:3^5\)
b)\(16\cdot2^4\cdot\frac{1}{32}\cdot2^3\)
2. Tìm x:
a) \(\left(x-1\right)^5=32\)
b) \(\left(2^3:4\right)\cdot2^{\left(x+1\right)}=64\)
tìm x nguyên: \(2^{5\left(\frac{1}{2}\right)^{2x}< \left(\frac{1}{32}\right)^{12}}\)
\(1.\left(x-1\right)^5=32\\ 2.\left(x-3\right)^2+!y^2-25!=0\)xin lỗi mọi người ! là giá trị tuyệt đối
Tìm số nguyên x, nếu biết
\(\frac{^{2^{4-x}}}{16^5}=32^6\)
\(\frac{3^{2x+3}}{9^3}=9^{14}\)
\(\left(-2\right)^x=-\frac{\left(-8^4\right)}{\left(-32\right)^3}\)
\(\left(-5^x\right)=\frac{25^{10}}{\left(-5\right)^{17}}\)
\(^{\left(x-1\right)^5=-32}\)
\(\left(x-1^5\right)=-32\)
tìm x, y
\(a.\left(x-5\right)^2=\left(1-3x\right)^2\)
\(b.\left(x+5\right)^2+\left(3y-9\right)^4=0\)
\(c.\frac{1}{8}.16^x=2^x\)
\(d.2^{x-1}+5.2^{x-2}=\frac{7}{32}\)