\(\left(x-1\right)^5-\left(x-1\right)^4=0.\)
\(\Leftrightarrow\left(x-1\right)^4\left(x-1-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)^4\left(x-2\right)=0\)
\(\orbr{\begin{cases}\left(x-1\right)^4=0\\\left(x-2\right)=0\end{cases}}\orbr{\begin{cases}x-1=0\\x=2\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=2\end{cases}}\)
Vậy x=1 ; x=2