(x - 1)5 = -32
=> x - 1 = -2
x = -2 + 1
x = -1.
\((x-1)^5 =(-2)^ 5\)
\(x-1=-2\)
\(x =-2+1\)
\(x= -1\)
(x-1)5= -32
(x-1)5= (-2)5
x-1= -2
x= -2+1
x= -1
Vậy x= -1
Ko bt có đúng ko :)))
`(x-1)^5=-32`
`=>(x-1)^5=(-2)^5`
`=>x-1=-2`
`=>x=-1`
(x - 1)5 = (- 2)5
x - 1 = - 2
x = - 2 + 1
x = - 1