Question

\(\left(x-1\right)^2+\left(y-1\right)^2=4\)

Answer 1

Đề có cho x,y nguyên ko bạn nếu ko thì có nhìu x;y

Answer 2

Vi  \(\left(x-1\right)^2\) co so mu chan \(\Rightarrow\left(x-1\right)^2\ge0\) va \(\left(x-1\right)^2\) la so chinh phuong

Vi \(\left(y-1\right)^2\) co so mu chan  \(\Rightarrow\left(y-1\right)^2\ge0\) va \(\left(y-1\right)^2\) la so chinh phuong

Ma \(\left(x-1\right)^2+\left(y-1\right)^2=4\)

Nen ta co bang sau:

\(\left(x-1\right)^2\)	0	1	4
\(\left(y-1\right)^2\)	4	3	0
x	1	2	3
y	3	khong co	1

Vay \(\left(x;y\right)\in\left\{\left(1;3\right);\left(3;1\right)\right\}\)