( x -15) = -32 => x - 1 = -32
=> x = -31
\(\left(x-1^5\right)=-32\)
=> \(x-1^5=-32\)
=> \(x-1=-32\)
=> \(x=-32+1=-31\)
Vậy \(x=-31\)
\(\left(x-1\right)^5=-32\)
\(\Rightarrow\left(x-1\right)^5=\left(-2\right)^5\)
\(\Rightarrow x-1=-2\)
\(\Rightarrow x=-1\)
tíc mình nha