Question

\(\left(\sqrt{x}-1+5\right)\times\left(x-6\times\sqrt{x}\right)=0\)

Answer 1

ĐKXĐ : x\(\ge0\)

Ta có: \(\left(\sqrt{x}+4\right)\left(x-6\sqrt{x}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\sqrt{x}+4=0\\x-6\sqrt{x}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}\sqrt{x}=-4\left(L\right)\\\sqrt{x}\left(\sqrt{x}-6\right)=0\end{cases}}\)

=>\(\orbr{\begin{cases}\sqrt{x}=0\\\sqrt{x}-6=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\\sqrt{x}=6\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=36\end{cases}}}\)