\(\left(\frac{3}{4}x-5\right)^2=\frac{9}{49}\)
\(\frac{3}{4}x-5=\sqrt{\frac{9}{49}}\)
\(\frac{3}{4}x-5=\frac{3}{7}\)
\(\frac{3}{4}x=\frac{3}{7}+5\)
\(\frac{3}{4}x=\frac{38}{7}\)
\(x=\frac{38}{7}:\frac{3}{4}\)
\(x=\frac{38}{7}\cdot\frac{4}{3}\)
\(x=\frac{152}{21}\)
\(\left(\frac{3}{4}x-5\right)^2=\frac{9}{49}=\left(\frac{3}{7}\right)^2=\left(-\frac{3}{7}\right)^2\)
=> 3/4 .x - 5 = 3/7 hoặc 3/4 . x - 5 = -3/7
(+) \(\frac{3}{4}x-5=\frac{3}{7}\Leftrightarrow\frac{3}{4}x=\frac{3}{7}+5\)
\(\frac{3}{4}x=\frac{38}{7}\) => \(x=\frac{38}{7}:\frac{3}{4}=\frac{152}{21}\)
(+) \(\frac{3}{4}x-5=-\frac{3}{7}\)
=> \(\frac{3}{4}x=-\frac{3}{7}+5=\frac{32}{7}\Rightarrow x=\frac{32}{7}:\frac{3}{4}=\frac{128}{21}\)
\(\left(\frac{3}{4}x-5\right)^2=\frac{9}{49}\)
\(\left(\frac{3}{4}x-5\right)^2=\left(\frac{3}{7}\right)^2\text{ hoặc }\left(\frac{3}{4}x-5\right)^2=\left(-\frac{3}{7}\right)^2\)
\(\Rightarrow\frac{3}{4}x-5=\frac{3}{7}\text{ hoặc }\frac{3}{4}x-5=-\frac{3}{7}\)
\(\frac{3}{4}x=\frac{3}{7}+5\text{ hoặc }\frac{3}{4}x=\frac{-3}{7}+5\)
\(\frac{3}{4}x=\frac{3}{7}+\frac{35}{7}\text{ hoặc }\frac{3}{4}x=\frac{-3}{7}+\frac{35}{7}\)
\(\frac{3}{4}x=\frac{38}{7}\text{ hoặc }\frac{3}{4}x=\frac{32}{7}\)
\(x=\frac{38}{7}:\frac{3}{4}\text{ hoặc }x=\frac{32}{7}:\frac{3}{4}\)
\(x=\frac{38}{7}.\frac{4}{3}\text{ hoặc }x=\frac{32}{7}.\frac{4}{3}\)
\(x=\frac{152}{21}\text{ hoặc }x=\frac{128}{21}\)
