Tìm a,b,c sao cho
a, \(\frac{1}{x\left(x+1\right).\left(x+2\right)}=\frac{a}{x}+\frac{b}{x+1}+\frac{c}{x+2}\)
cac ban oi giup minh di. minh dang can gap lam. lam on
Bài 1: Tìm x biết
\(\frac{\left(2009-x\right)^2+\left(2009-x\right).\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right).\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)
cac ban oi giup minh di. minh dang can gap lam. chieu minh di hoc roi. lam on
Bài 1: Cho A=\(\left(\frac{1}{3}+\frac{3}{x^2-3x}\right):\left(\frac{x^2}{27-3x^2}+\frac{1}{x+3}\right)\)
a, Rút gọn A
b, Tìm x để A<-1
cac ban oi giup minh di minh dang can gap lam. ai giup minh hên nhat nam 2016
bài 1 cho a,b,c>0: CMR
a, \(\frac{1}{a}+\frac{1}{b}>\frac{4}{a+b}\)
b, \(\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right).\left(a+b+c\right)>=9\)
cac ban giup minh di minh k hieu bai nay lam kieu j. minh dang can. cac ban oi lam on giup minh
giúp mình với
Tìm x
a)\(\left(2x-1\right)^3+\left(3-x\right)^3=\left(x+2\right)^3\)
b)\(\frac{1}{2x-5}+\frac{1}{x+8}+\frac{1}{2017-x}=\frac{1}{2020}\)
Thanks!
Cho a,b,c,d>0 va abcd=1 Chung minh
\(\frac{1}{\left(1+a\right)^2}\)+\(\frac{1}{\left(1+b\right)^2}\)+\(\frac{1}{\left(1+c\right)^2}\)+\(\frac{1}{\left(1+d\right)^2}\)>1
GIUP MK VOI CAC BAN OI
THANKS CAC BAN NHIEU
Giải phương trình
\(\frac{1}{2}\left(\frac{2x-2}{2009}+\frac{2x}{2010}+\frac{2x+2}{2011}\right)=\frac{33}{10}-\left(\frac{x+1}{2011}+\frac{x-1}{2009}+\frac{x}{2010}\right)\)
Tính
\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}+....+\frac{1}{\left(x+2019\right)\left(x+2020\right)}\)
tính(rút gọn)
a,\(\left(x+3-\frac{1}{x+3}\right)\left(x+\frac{3}{x+4}\right)\)
b,\(\left(2x-4-\frac{x-12}{3x+4}\right)\left(3x-2-\frac{10}{2x+1}\right)\)
c,\(\left(2x-8-\frac{x+10}{3x+1}\right)\left(x-6-\frac{x-6}{3x+2}\right)\)
d,\(\left(1+\frac{1}{x}\right):\left(1-\frac{1}{x^2}\right)\)