\(\left(\frac{2}{3}\right)^{x-2}=\left(\frac{16}{81}\right)^{x+1}\)
\(\Leftrightarrow\left(\frac{2}{3}\right)^{x-2}=\left[\left(\frac{2}{3}\right)^4\right]^{x+1}\)
\(\Leftrightarrow\left(\frac{2}{3}\right)^{x-2}=\left(\frac{2}{3}\right)^{4\left(x+1\right)}\)
\(\Leftrightarrow x-2=4x+4\)
\(\Leftrightarrow-3x=6\Leftrightarrow x=-2\)
Tìm x biết
a) \(\left(\frac{3}{5}\right)^5.x=\left(\frac{3}{7}\right)^7\)
b) \(\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\)
c) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
d) \(\left(x+\frac{1}{4}\right)^4=\frac{16}{81}\)
Ai xong nhanh nhất cho 1 like \(☺\)
Tìm x biết
a)\(\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\) b) \(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\) c) \(\left(x+\frac{1}{2}\right)^4=\frac{16}{81}\)
\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\) \(\left(-\frac{1}{3}\right)^3\times x=\frac{1}{81}\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\) \(\left(x+\frac{1}{2}\right)^4=\frac{16}{81}\)
cho đa thức \(f\left(x\right)=4\cdot x^2+3x+1\); \(g\left(x\right)=3x^2-2x+1\); \(k\left(x\right)=7\cdot x^2-35x+42\)
a) tính f(x)-g(x)=h(x)
b) tính nghiệm của h(x) và k(x)
c) tìm gia trị của đa thức h(x) biết:
\(\left(x^2-9\right)^{2021}=\left(\frac{3}{4}-81\right)\cdot\left(\frac{3^2}{5}-81\right)^2\cdot\left(\frac{3^2}{6}-81\right)^3\cdot\cdot\cdot\left(\frac{3^{2020}}{2023}-81\right)^{2020}\)
tìm x biết : a,\(\frac{x^7}{81}=27\); b,\(\frac{x^8}{9}=729\); c.\(^{\left[x-\frac{1}{2}\right]^0}\); d,\(\left[X-2\right]^2=1\); e, \(\left[2X-1\right]^3=8\); f,\(\left[X+\frac{1}{2}\right]^2\)=\(\frac{1}{16}\)
a)\(\left(\frac{1}{13}\right)^{13}:\left(\frac{1}{3}\right)^{x-2}=\frac{1}{81}\)
b)\(\left(0,4\right)^{x-1}:\left(\frac{2}{5}\right)^2=\frac{8}{125}\)
Tìm x biết : \(\left(\frac{1}{3}\right)^x\left(\frac{1}{9}\right)^x\left(\frac{1}{27}\right)^x\left(\frac{1}{81}\right)^x\left(\frac{1}{243}\right)^x=\left(-\frac{1}{3}\right)^{30}\)
Tính
\(\frac{16}{2^{^x}}=2\)
\(\frac{\left(-3\right)^x}{81}=-27\)
\(8^x:2^{10}\)
\(\left(\frac{2^2}{4^2}.\frac{2^3}{16}\right)^{15}:\left(\frac{2^6}{16^2}\right)^{10}\)
\(\frac{12^3+3.12^2+3^3}{162}\)
Giúp mk vs huhuhu ToT
mọi người giúp nhé cần gấp
\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\frac{2}{3}\times3^{x+1}-7\times3^x=-405\)
\(\frac{3}{1-2x}=\frac{-5}{3x-2}\)
\(\left(x-3\right)^{4^{ }}=\frac{16}{81}\)
