(1/3)^2-x-1=3^5
x=(1/3)^2x-1=243
x=(1/3)^2x=243-1
x=(1/3)^2x=242
x=1/9.x=242
x=242:1/9
x=26,88
(1/3)^2-x-1=3^5
x=(1/3)^2x-1=243
x=(1/3)^2x=243-1
x=(1/3)^2x=242
x=1/9.x=242
x=242:1/9
x=26,88
Tìm x và y biết:
d)\(-1\frac{2}{3}-\left(\left|2x\right|+\frac{5}{6}\right)=\)\(-2\)e)\(\left(-\frac{1}{2}+\frac{1}{3}\right):\left|1-2x\right|-1\frac{1}{4}:\left(-\frac{5}{8}\right).\left(-\frac{1}{2}\right)^2=\frac{1}{3}\)
c)\(\left|2x-1\right|+\left|2y+1\right|+\left|2x-y\right|=0\)b)\(\left|2x-1\right|=2x-1\)
a)\(\left|x-3\right|=x+4\)
Tìm x:
a)\(2.\left(3x-\frac{1}{2}\right)-2x=\frac{1}{2}\left(2x-3\right)\)
b)\(\left(2x-\frac{3}{5}\right)^2=\frac{4}{25}\)
c)\(\left(3x-1\right)^3=27\)
d)\(5-\left|x\right|=2\)
e)|2x+1|-3=3
f)|3-2x|=5
\(\left(5-x\right)\left(3x-\frac{1}{4}\right)=0\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
a) \(\frac{3}{2}\left(1-\frac{1}{2}x\right)-5=4-3\left(2x-3\right)\)
b) \(\left(\frac{4}{5}-\frac{3}{2}x\right):\left(\frac{1}{2}-\frac{1}{5}\right)=\frac{2}{3}x-1\)
a. \(\frac{2-x}{4}=\frac{x+1}{-3}\)
b. \(\frac{2-5x}{3}=\frac{-4x+1}{-5}\)
c. \(3\left(x-1\right)+4\left(5x+2\right)=3\)
d. \(\frac{1}{3}\left(2x-1\right)-4\left(5-2x\right)=\left(x+1\right)\)
\(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=5\)5
\(A=\left(\frac{1}{38}-1\right).\left(\frac{1}{37}-1\right).\left(\frac{1}{36}-1\right)...\left(\frac{1}{2}-1\right)\)
Làm chi tiết nhé
a) 3x- 2 Ix-1I = 5
b) \(\frac{3}{2}\left(1-\frac{1}{2}x\right)-5=4-3\left(2x-3\right)\)
c) \(\left(\frac{4}{5}-\frac{3}{2}x\right):\left(\frac{1}{2}-\frac{1}{5}\right)=\frac{2}{3}x-1\)
rút gọn
\(\frac{2}{2x+3}+\frac{3}{2x+1}-\frac{6x+5}{\left(2x+3\right)\left(2x-3\right)}\)
Tìm x biết:
\(\frac{-1}{2}\times\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\times\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
\(A=\frac{2^{12}x3^5-4^6x9^2}{\left(2^2x3\right)^6+8^4x3^5}-\frac{5^{10}x7^3-25^5x49^2}{\left(125x7\right)^3+5^9x14^3}\)
\(B=\frac{\left(\frac{-1}{2}\right)^3-\left(\frac{3}{4}\right)^3x\left(-2\right)^2}{2x\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
\(C=2^2+3\left(\frac{1}{2}\right)^0-2^{-2}+\left[\left(-2^2\right):\frac{1}{2}\right]:8\)