Giải phương trình:
\(\left(\frac{1}{1.51}+\frac{1}{2.52}+\frac{1}{3.53}+......+\frac{1}{10.60}\right)x=\frac{1}{1.11}+\frac{1}{2.12}+\frac{1}{3.13}+......+\frac{1}{50.60}\)
giải phương trình
\(\left(\frac{1}{1.51}+\frac{1}{2.52}+\frac{1}{3.53}+...+\frac{1}{10.60}\right).x=\left(\frac{1}{1.11}+\frac{1}{2.12}+\frac{1}{3.13}+...+\frac{1}{50.60}\right)\)
Giải phương trình:(1/1.51+1/2.52+1/3.53+....1/10.60).x=1/1.11+1/2.12+1/3.13+..........+1/50.60
giải phương trình (1/1.51+1/2.52+1/3.53+.....+1/10.60).x=(1/1.11+1/2.12+1/3.13+....+1/50.60)
Giải pt
(1/1.51+1/2.52+1/3.53+.....+1/10.60).x=(1/1.11+1/2.12+1/3.13+....+1/50.60)
Giải phương trình :\(\left(\frac{1}{1.101}+\frac{1}{2.102}+\frac{1}{3.103}+...+\frac{1}{10.110}\right).x=\frac{1}{1.11}+\frac{1}{2.12}+...+\frac{1}{100.110}\)
Giúp mình với các bạn::
Chứng minh:
a) \(\frac{1}{n}-\frac{1}{n+1}=\frac{1}{n\left(n+1\right)}\)
b) \(\frac{1}{10}\left(\frac{1}{n}-\frac{1}{n+10}\right)=\frac{1}{n\left(n+10\right)}\)
c)Tổng quát: \(\frac{1}{a}\left(\frac{1}{n}-\frac{1}{n+a}\right)=\frac{1}{n\left(n+a\right)}\)
Áp dụng tính tổng sau: \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2014.2015}\)
Áp dụng giải phương trình sau:
\(\left(\frac{1}{1.101}+\frac{1}{2.102}+\frac{1}{3.103}+...+\frac{1}{10.110}\right)x=\left(\frac{1}{1.11}+\frac{1}{2.12}+\frac{1}{3.13}+...+\frac{1}{100.10}\right)\)
Câu 1: Tìm x biết:
a)\(\left|x+\frac{1}{101}\right|+\left|x+\frac{2}{101}\right|+\left|x+\frac{3}{101}\right|+...+\left|x+\frac{100}{101}\right|=101x\)
b)\(\left|x+\frac{1}{1.3}\right|+\left|x+\frac{1}{3.5}\right|+\left|x+\frac{1}{5.7}\right|+...+\left|x+\frac{1}{97.99}\right|=50x\)
c)\(\left|x+\frac{1}{1.2}\right|+\left|x+\frac{1}{2.3}\right|+\left|x+\frac{1}{3.4}\right|+...+\left|x+\frac{1}{99.100}\right|=100x\)
d)\(\left|x+\frac{1}{1.5}\right|+\left|x+\frac{1}{5.9}\right|+\left|x+\frac{1}{9.13}\right|+...+\left|x+\frac{1}{397.401}\right|=101x\)
CMR: \(\frac{1}{\left(x+y\right)^3}.\left(\frac{1}{x^3}+\frac{1}{y^3}\right)+\frac{3}{\left(x+y\right)^4}.\left(\frac{1}{x^2}+\frac{1}{y^2}\right)+\frac{6}{\left(x+y\right)^5}.\left(\frac{1}{x}+\frac{1}{y}\right)=\frac{1}{x^3y^3}\)