\(=\left(-\frac{5}{132}-\frac{5}{3}\right)-\left(-\frac{5}{4}+\frac{6}{11}\right)\)
\(=-\frac{75}{44}-\left(-\frac{5}{4}+\frac{6}{11}\right)\)
\(=-\frac{75}{44}+\frac{31}{44}\)
\(=-1\)
( \(\frac{-1}{4}\)+ \(\frac{7}{33}\)- \(\frac{5}{3}\) ) - ( \(\frac{-5}{4}\) + \(\frac{6}{11}\))
= ( \(\frac{-1}{4}\)\(\frac{-48}{33}\)) - ( \(\frac{-31}{44}\))
= \(\frac{-1}{4}\)+ \(\frac{-48}{33}\)+ \(\frac{-31}{44}\)
= ( \(\frac{-1}{4}\)+ \(\frac{-31}{44}\)) + \(\frac{-48}{33}\)
= \(\frac{-5}{11}\) + \(\frac{-48}{33}\)
= \(\frac{-21}{11}\)
HỌC TỐT ^^__^^
\(\left(\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}\right)-\left(\frac{-5}{4}+\frac{6}{11}\right)\)
\(=\frac{-1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{5}{4}-\frac{6}{11}\)
\(=\left(\frac{-1}{4}+\frac{5}{4}\right)+\left(\frac{7}{33}-\frac{6}{11}\right)-\frac{5}{3}\)
\(=1+\left(\frac{-1}{3}\right)-\frac{5}{3}=1+\left(\frac{-1}{3}-\frac{5}{3}\right)=1+\left(-2\right)=-1\)
Cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt^^
