\(110\%x+115\%y=400\\ \Rightarrow1.1x+1.15y=400\\ x+y=360\\ \Leftrightarrow1.1\left(x+y\right)=360\cdot1.1=396\\ \Rightarrow\left(1.1x+1.15y\right)-1.1\left(x+y\right)=1.1x+1.15y-1.1x-1.1y=0.05y=4\\ \Leftrightarrow y=\dfrac{4}{0.05}=80\\ \Rightarrow x=360-80=280.\)
\(\left\{{}\begin{matrix}x+y=360\\112\%x+110\%y=400\end{matrix}\right.\)
giải hệ phương trình
a) \(\left\{{}\begin{matrix}x+2y=2\\-2x+y=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}3x-2y=4\\2x+y=5\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}2y-x=2\\2x-y=-1\end{matrix}\right.\)
giúp tui giải bài này với
tui c.ơn trước
giải hệ:
\(\left\{{}\begin{matrix}x+2y=7\\x^2+y^2-2xy=1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x-y=2\\x^2+y^2+164\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x-y+xy=-13\\x^2+y^2-x-y=32\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x-y=3\\x^3-y^3=7\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\dfrac{3}{x-1}-\dfrac{1}{y+2}=\dfrac{3}{4}\\\dfrac{5}{x-1}+\dfrac{3}{y+2}=\dfrac{29}{12}\end{matrix}\right.\)giải chi tiết giúp mình nha☘⚽✿❤ mình cảm ơn nha
(1) giải hpt:
a) \(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{6}^{ }\\\dfrac{8}{x}+\dfrac{5}{y}=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{x-1}{2}-y=1\\2x+y=1\end{matrix}\right.\)
giúp mk vs ak
(1) giải hpt:
a) \(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{6}\\\dfrac{8}{x}+\dfrac{5}{y}=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{x-1}{2}-y=1\\2x+y=1\end{matrix}\right.\)
giúp mk vs ạ
Giải các hệ phương trình:
a)\(\left\{{}\begin{matrix}\dfrac{x}{y}=\dfrac{2}{3}\\x+y-10=0\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\left(3x+2\right)\left(2y-3\right)=6xy\\\left(4x+5\right)\left(y-5\right)=4xy\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\left(2x-3\right)\left(2y+4\right)=4x\left(y-3\right)+54\\\left(x+1\right)\left(3y-3\right)=3y\left(x+1\right)-12\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{2y-5x}{3}+5=\dfrac{y+27}{4}-2x\\\dfrac{x+1}{3}+y=\dfrac{6y-5x}{7}\end{matrix}\right.\)
giải hệ phương trình
a
\(\left\{{}\begin{matrix}x+y=1\\x-y=-5\end{matrix}\right.\)
b.
\(\left\{{}\begin{matrix}2x+2y=5\\x-2y=1\end{matrix}\right.\)
c.
\(\left\{{}\begin{matrix}2x+3y=5\\3x-2y=1\end{matrix}\right.\)
Giải hệ phương trình
a)\(\left\{{}\begin{matrix}x+y=6\\\\2x-3y=12\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}x-y=5\\\left(x-2\right)\left(y+3\right)=3+xy\end{matrix}\right.\)
