Question

\(\left(3x^5-2x^2+4x^2\right):2x^2\)

Answer 1

\(=3x^5:2x^2-2x^2:2x^2+4x^2:2x^2=\dfrac{3}{2}x^3-1+2=\dfrac{3}{2}x^3+1\)

Answer 2

  

Answer 3

\(\left(3x^5-2x^2+4x^2\right):2x^2=\dfrac{3}{2}x^3-1+2=\dfrac{3}{2}x^3+1\)

Answer 4

`(3x^5 - 2x^2 + 4x^2)  : 2x^2`

`= 3x^5 : 2x^2 - 2x^2 : 2x^2 + 4x^2 : 2x^2`

`= (3:2)x^(5-2) - (2:2)x^(2-2) + (4:2)x^(2-2)`

`= 3/2x^3 - 1x^0 + 2x^0`

`= 3/2x^3 - 1 . 1 + 2 . 1`

`= 3/2x^3 - 1 + 2`

`= 3/2x^3 + 1`