\(\Leftrightarrow\left(3x-1\right)^2-4^2=0\)
\(\Leftrightarrow\left(3x-1-4\right)\left(3x-1+4\right)=0\)
\(\Leftrightarrow\left(3x-5\right)\left(3x+3\right)=0\Leftrightarrow\orbr{\begin{cases}3x-5=0\\3x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}}\)
\(\left(3x-1\right)^2-16=\)
Bai phan tich da thuc thanh nhan tu dung hang dang thuc (Cua lop 8 nha)
Lam day du va chinh xac nha!
phan tich da thuc thanh nhan tu
\(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-24\)
ban nao giai ho mk bai nay voi
mk se tik cho
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
phan tich da thuc thanh nhan tu bang phuong phap dung hang dang thuc
1)tinh nhanh
a)72 -272 =?
b)372 -132=?
c)20022-22=?
giai giup minh nha
phan tich da thuc thanh nhan tu bang pp dung hang dang thuc:
a) 16x^2 - (x^2 + 4)^2
b) 27x^3 - 54x^2 + 36x - 8
c) (x+y)^3 - (x-y)^3
help me
phan tich da thuc thanh nhan tu
\(9\left(x+1\right)^2-\left(3x-2\right)^2\)
\(\left(2x-10\right).\left(x+10\right).\left(x+\sqrt{3}\right)=0\)
(Bai phan tich da thuc thanh nhan tu)
\(\left(2x+1\right)^2+2\left(2x+1\right)\)
phan tich da thuc thanh nhan tu
phan tich thanh nhan tu bang pp dung hang dang thuc 1+8x^6y^3
