\(\left(35\%+\frac{1}{4}+75\%+0,65\right)\cdot105+\left(\frac{1}{2}+50\%\right)\)
\(=\left(\frac{7}{20}+\frac{1}{4}+\frac{3}{4}+\frac{13}{20}\right)\cdot105+\left(\frac{1}{2}+\frac{1}{2}\right)\)
\(=2\cdot105+1\)
\(=211\)
\(=210x+1\)
\(\left(\frac{1}{4}+35\%+0,65+75\%\right)X\left(1\frac{6}{3}+4\frac{8}{24}\right)\)
X là nhân
1.Tính giá trị biểu thức:
\(A=\)\(\left[\frac{1}{4}+35\%+0,65+75\%\right]x\)\(\left[1\frac{6}{9}+4\frac{8}{24}\right]\)
2.So sánh:
\(B=\frac{19}{20}+\frac{29}{30}+\frac{41}{40}+\frac{55}{56}+\frac{71}{72}+\frac{89}{90}\) \(C=6\frac{2010}{2011}\)
tìm x
\(\left(x+\frac{1}{2\cdot4}\right)+\left(x+\frac{1}{4\cdot6}\right)+\left(x+\frac{1}{6\cdot8}\right)+\left(x+\frac{1}{8\cdot10}\right)+\left(x+\frac{1}{10\cdot12}\right)=50\frac{5}{24}\)
\(\frac{\left(\frac{1}{2}+0,25+\frac{1}{4}\right)+\left(\frac{1}{8}+\frac{3}{2}+\frac{1}{8}+\frac{25}{100}\right)+\left(0,75+\frac{1}{2}+50\%+\frac{1}{4}+0,55+\frac{145}{100}\right)}{1x2x3}\)
tính nhanh:\(\frac{\left(\frac{1}{2}+0,25+\frac{1}{4}\right)+\left(\frac{1}{8}+\frac{3}{2}+\frac{1}{8}+\frac{25}{100}\right)+\left(0,75+\frac{1}{5}+50\%+\frac{1}{4}+0,55+\frac{45}{100}\right)}{1x2x3}\)
Tìm X:
\(\left[\left(35\frac{5}{7}+2\frac{3}{4}\right)-5\frac{5}{7}+\frac{1}{4}\right]:\left(11+X\right)=3\)
1) \(79\frac{19}{35}.\frac{7}{90}+15\frac{16}{35}.\frac{7}{90}\)
2)\(\left(3\frac{1}{5}-\frac{1}{11}\right).11\)
3)\(4\frac{1}{5}:\left(2\frac{1}{3}.1\frac{2}{5}\right)\)
4)\(13,2.\frac{15}{64}-\left(\frac{4}{5}+\frac{2}{3}\right):3\frac{2}{3}\)
\(A=\left(2017-\frac{1}{4}-\frac{2}{5}-\frac{3}{6}-...-\frac{2017}{2020}\right):\left(\frac{1}{20}+\frac{1}{25}+\frac{1}{30}+\frac{1}{35}+...+\frac{1}{10100}\right)\)
\(A=5,3:\left(5\frac{5}{28}-2\frac{13}{36}+1\frac{16}{63}\right)\)
\(B=\left(\frac{19}{10}\times\frac{19}{10}+\frac{39}{2}:\frac{13}{3}\right)\times\left(\frac{62}{75}-\frac{12}{75}\right)\)
