(3 - x)2 - x(x + 1) = 3
9 - 6x + x2 - x2 - x = 3
9 - 7x = 3
- 7x = - 6
x = \(\frac{6}{7}\)
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(3 - x)2 - x(x + 1) = 3
9 - 6x + x2 - x2 - x = 3
9 - 7x = 3
- 7x = - 6
x = \(\frac{6}{7}\)
rút gọn biểu thức sau bằng cách nhanh nhất
A = \(\left(a^2+b^2-c^2\right)^2-\left(a^2-b^2+c^2\right)^2-4a^2b^2\)
B = \(\left(3x^3+3x+1\right)\cdot\left(3x^3-3x+1\right)-\left(3x^3+1\right)^2\)
C = \(\left(2-6x\right)^2+\left(2-5x\right)^2+2\cdot\left(6x-2\right)\cdot\left(2-5x\right)\)
D = \(5\cdot\left(3x-1\right)^2+4\cdot\left(5x+1\right)^2-12\cdot\left(5x-2\right)\left(5x+2\right)\)
E = \(\left(3x-1\right)^2+\left(2x+4\right)\cdot\left(1-3x\right)+\left(x+2\right)^2\)
G = \(\left(x-1\right)^3+4\cdot\left(x+1\right)\cdot\left(1-x\right)+3\cdot\left(x-1\right)\cdot\left(x^2+x+1\right)\)
Làm giúp mình nha
\(a,\left(x-2\right)\cdot\left(x+2\right)\cdot\left(x^2-10\right)=72\)
\(b,\left(x+1\right)\cdot\left(x+2\right)\cdot\left(x+3\right)\cdot\left(x+4\right)\cdot\left(x+5\right)=40\)
\(c,\left(2x-5\right)^2=\left(4x+7\right)^2\)
\(d,\left(2x^2+3x-1\right)^2-5\cdot\left(2x^2+3x+3\right)+24=0\)
Phân tích đa thức thành nhân tử
a)\(x\cdot\left(x+1\right)\cdot\left(x+2\right)\cdot\left(x+3\right)+1\)
b)\(\left(x^2-x+2\right)^2+4\cdot x^2-4\cdot x-4\)
c)\(\left(x+2\right)\cdot\left(x+4\right)\cdot\left(x+6\right)\cdot\left(x+8\right)+16\)
Giải phương trình
a. \(\frac{1}{27}\cdot\left(x-3\right)^3-\frac{1}{125}\cdot\left(x-5\right)^3=0\)
b.\(125x^3-\left(2x+1\right)^3-\left(3x-1\right)^3=0\)
c.\(\left(x-3\right)^3+\left(x+1\right)^3=8\cdot\left(x-1\right)^3\)
d.\(\left(x^2-3x+2\right)\cdot\left(x^2+15x+56\right)+8=0\)
e.\(\left(2x^2-3x+1\right)\cdot\left(2x^2+5x+1\right)-9x^2=0\)
f.\(\left(x+6\right)^4+\left(x+8\right)^4=272\)
Rút gọn:
\(\frac{1}{\left(x+y\right)^3}\cdot\left(\frac{1}{x^3}+\frac{1}{y^3}\right)+\frac{3}{\left(x+y\right)^4}\cdot\left(\frac{1}{x^2}+\frac{1}{y^2}\right)+\frac{6}{\left(x+y\right)^5}\cdot\left(\frac{1}{x}+\frac{1}{y}\right)\)
\(\frac{1}{\left(x+y\right)^2}\cdot\left(\frac{1}{x^3}+\frac{1}{y^3}\right)+\frac{3}{\left(x+y\right)^{\text{4}}}\cdot\left(\frac{1}{x^2}+\frac{1}{y^2}\right)+\frac{6}{\left(x+y\right)^5}\cdot\left(\frac{1}{x}+\frac{1}{y}\right)\)
Giúp vs cần gấp
Rút Gọn:
\(a:\left(x+1\right)-\left(x-1\right)-3\cdot\left(x+1\right)\cdot\left(x-1\right)\)
\(b:5\cdot\left(x+2\right)\cdot\left(x-2\right)-\frac{1}{2}\cdot\left(6-8x\right)^2+17\)
\(P=\left[\left(x^4-x+\frac{x-3}{x^3+1}\right)\cdot\left(\frac{\left(x^3-2x^2-2x-1\right)\cdot\left(x+1\right)}{x^9+x^7-3x^2-3}\right)+1-\frac{2\left(x+6\right)}{x^2+1}\right]\cdot\frac{4x^2+4x+1}{\left(x+3\right)\left(4-x\right)}\)
a, Tìm ĐKXD của P
b,Rút Gọn P
c,Chứng Minh Với các giá trị của x mà biểu thức P có nghĩa thì \(-5\le P\le0\)
Tìm giá trị của biểu thức : \(C=\frac{4x^4+1}{4\left(x+1\right)^2+1}\cdot\frac{4\left(x+2\right)^4+1}{4\left(x+3\right)^4+1}\cdot\cdot\cdot\frac{4\left(x+10\right)^4+1}{4\left(x+11\right)^4+1}\)
Giải phương trình sau: \(\left(6\cdot x+7\right)^2\cdot\left(3\cdot x+4\right)\cdot\left(x+1\right)=6\)