Đặt 2x - 3 = t
Ta có t^4 = t^6 => t^6 - t^44 = 0
=> t^4 ( t^2 - 1 ) = 0
=> t^4 ( t- 1 )( t+ 1 ) = 0
=> t^4 = 0 hoặc t - 1 = 0 hoặc t + 1 = 0
=> t = 0 hoặ t = 1 hoặc t = - 1
(+) t = 0 => 2x - 3 = 0 => x = 3/2
(+) t = 1 => 2x - 3 = 1 => 2x = 4 => x = 2
(+) t = -1 => 2x - 3 = -1 => 2x = 2 => x = 1
VẬy x = ( 1;3/2;2}
tim so huu ti x biet :
a)\(\left(2x-3\right)^4=\left(2x-3\right)^6\)
b) \(\left(3x+5\right)^3=\left(3x+5\right)^{2016}\)
c) \(\left(2x+1\right)^{2015}=\left(2x+1\right)^{2017}\)
tim x
a, \(\left(x+1\right)\left(2-x\right)\left(3+x^2\right)\ge0\)
b, \(\left(2x+1\right)\left(x+3\right)\left(x-5\right)>0\)
c,\(\frac{\left(3x-6\right)\left(x-4\right)}{x+3}< 0\)
Tìm x biết:
\(a.\left|2x-3\right|=x-2\\ b.\left(2x+3\right)^6-\left(2x+3\right)^4=0\)
\(\left(2x+1\right)^4=\left(2x+1\right)^6\)
Tim x
Baì 1 tìm x
a) \(\left(2x-3\right)^4+\left(2x-3\right)^6\)
b)\(\left(2x+1\right)^5=\left(2x+1\right)^6\)
c)\(3^3+3^{x+3}=756\)
Bài 4 : Tìm \(x\), biết :
a ) \(\left|4-2x\right|+\left|x+3\right|=8\)
b ) \(\left|x+1\right|+\left|x-2\right|+\left|x+3\right|=6\)
c ) \(\left|x-2\right|+\left|x-3\right|+\left|4-x\right|=2\)
d ) \(2\left|x+2\right|+\left|4-3x\right|=11\)
e ) \(\left|2x-1\right|+\left|2x-5\right|=4\)
g ) \(\left|x-3\right|+\left|3x+4\right|=\left|2x+1\right|\)
Tìm x và y biết:
d)\(-1\frac{2}{3}-\left(\left|2x\right|+\frac{5}{6}\right)=\)\(-2\)e)\(\left(-\frac{1}{2}+\frac{1}{3}\right):\left|1-2x\right|-1\frac{1}{4}:\left(-\frac{5}{8}\right).\left(-\frac{1}{2}\right)^2=\frac{1}{3}\)
c)\(\left|2x-1\right|+\left|2y+1\right|+\left|2x-y\right|=0\)b)\(\left|2x-1\right|=2x-1\)
a)\(\left|x-3\right|=x+4\)
tim x
a)\(2x\left(x-\frac{1}{7}\right)=0\)
b)\(\left(x-9\right).\left(x+\frac{3}{5}\right)=0\)
c)\(\left(\frac{-4}{7}-2x\right)\left(x-\frac{5}{4}\right)=0\)
a, \(\text{[}\left(x-y\right)^3+3\left(x-y\right)\text{]}:\dfrac{1}{3}\left(x-y\right)\)
b, \(\left(8x^3-27y^3\right):\left(2x-3y\right)\)
c, \(\text{[}5\left(x+2y\right)^6-6\left(x+2y\right)^5\text{]}:2\left(x+2y\right)^4\)
