Ta có :
\(36=6^2\)
\(\Rightarrow\left(2x-3\right)^2=6^2\)
\(\Rightarrow\left(2x-3\right)=3\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
:)
(2x -3) 2 = 36
(2x - 3)2 = 62
=> 2x - 3 = 6
=> 2x = 9
=> x = 9 : 2
=> x = 9/2 = 4,5
(2x-3)2=36
\(\Rightarrow\)\(\orbr{\begin{cases}2x-3=6\\2x-3=-6\end{cases}\Rightarrow\orbr{\begin{cases}2x=9\\2x=-3\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{9}{2}\\x=\frac{-3}{2}\end{cases}}}\)
Ta có :
( 2x trừ 3 )^2 bằng 36
( 2x trừ 3 )^2 bằng 6^2
suy ra;
2x trừ 3 bằng 6
2x bằng 6 cộng 3
2x bằng 9
x bằng 9 chia 2
x bằng 4,5
\(\left(2x-3\right)^2=36\)
\(=\orbr{\begin{cases}\left(2x-3\right)^2=6^2\\\left(2x-3\right)^2=\left(-6\right)^2\end{cases}}\)
\(=\orbr{\begin{cases}2x-3=6\\2x-3=-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=6+3\\2x=-6+3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{2}=4,5\\x=-\frac{3}{2}=-1,5\end{cases}}\)
\(\Rightarrow x=\left\{\frac{9}{2};-\frac{3}{2}\right\}\)