Question

\(\left(2x-1\right)^{10}=49^5\)

Answer 1

\(\left(2x-1\right)^{10}=\dfrac{9}{25}\)

\(2x=\dfrac{9}{25}+1\)

\(2x=\dfrac{34}{25}\)

\(x=\dfrac{34}{25}:2\)

\(x=\dfrac{34}{50}=\dfrac{17}{25}\)

 

Answer 2

\(\left(2x-1\right)^{10}=49^5\)

\(\left(2x-1\right)^{10}=\left(7^2\right)^5\)

\(\left(2x-1\right)^{10}=7^{10}\)

\(\Rightarrow2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=\dfrac{8}{2}\)

\(x=4\)

Vậy \(x=4\)