Question

\(\left(2.\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}\right)\div\left(-\dfrac{3}{7}\right)\)

Answer 1

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Answer 2

\(=\dfrac{9}{680}:\dfrac{-3}{7}=\dfrac{-21}{680}\)

Answer 3

\(\left(2.\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}\right):\left(\dfrac{-3}{7}\right)\)

\(=\dfrac{9}{680}:\left(\dfrac{-3}{7}\right)\)

\(=\dfrac{9}{680}\cdot\left(-\dfrac{7}{3}\right)\)

\(=-\dfrac{21}{680}\)

Answer 4

\(\left(2.\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}\right):\left(-\dfrac{3}{7}\right)\)

\(=\dfrac{9}{680}:\left(-\dfrac{3}{7}\right)\)

\(=-\dfrac{21}{680}\)

Answer 5

( 2.2/15.9/17.3/32 ) : ( -3/7 ) = -21/680

Answer 6

=6809​:7−3​=680−21​