Question

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{2002}\right).\left(1+\frac{1}{2003}\right)\)

Answer 1

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)......\left(1+\frac{1}{2002}\right).\left(1+\frac{1}{2003}\right)\)

\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}....\frac{2003}{2002}.\frac{2004}{2003}\)

\(=\frac{2004}{2}=1002\)

Answer 2

(1+1/2)(1+1/3)(1+1/4)...(1+1/2003)=3/2.4/3.5/4.....2004/2003=3.4.5.....2004/2.3.4.....2003=2004/2=1002

Answer 3

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{2002}\right).\left(1+\frac{1}{2003}\right)\)

\(=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{2003}{2002}.\frac{2004}{2003}\)

\(=\frac{3.4.5...2003.2004}{2.3.4...2002.2003}\)

\(=\frac{2004}{2}=1002\)

Answer 4

=\(\frac{3}{2}.\frac{4}{3}.......\frac{2004}{2003}\)

=\(\frac{2004}{2}\)=

=\(1002\)

đ/s:.....