\(\overrightarrow{AB}\) = ( 3; -4) , \(\overrightarrow{u}\) = ( 3;-4) ; \(\overrightarrow{n}\) = ( 4;3)
PTTS: \(\left\{{}\begin{matrix}x=-2+3t\\y=4-4t\end{matrix}\right.\)
PTTQ: 4(x+2) +3( y-4)= 0
\(\Leftrightarrow\) 4x + 3y -4 = 0
PTCT: \(\frac{x+2}{3}=\frac{y-4}{-4}\)