Tui học lớp 7 đăng bài lớp 8 không được sao?
Tui học lớp 7 đăng bài lớp 8 không được sao?
Tính : \(\frac{x\left(y^2-z\right)+y\left(x-xy\right)}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}:\frac{\left(xy^2-xz\right)\left(2y-x\right)}{2\left(x^3+y^3+z^3-3xz\right)}\)
\(\frac{2x^2-4x+2y^2}{5x-5y}.\frac{16x^2-15y^2}{4x^3+4y^3}\)
1 ,lam tinh nhan :
a,\(x^2\left[5x^3-x-\frac{1}{2}\right]\)
b,\(\left[3xy-x^2+y\right]\frac{2}{3}x^2y\)
c[,\(4x^3-5xy+2x\)]\(\left[-\frac{1}{2}xy\right]\)
cac bn nao thong mjk thi tl lun nha
\(a.\left(5x^4-3x^3+x^2\right):3x^2=\frac{5}{3}x^2-x+\frac{1}{3}\)
\(b.\left(5xy^2+9xy-x^2y^2\right):\left(-xy\right)=-5y-9+xy\)
\(c.\left(x^3y^3-x^2y^3-x^3y^2\right):x^2y^2=xy-y-x\)
1. Thực hiện phép tính
a) \(\left(3x^2y-6xy+9x\right).\left(\frac{-4}{3xy}\right)\)
b) \(\left(\frac{1}{3}x+2y\right).\left(\frac{1}{9}x^2-\frac{2}{3}xy+4y^2\right)\)
c) (x-2) ( \(x^2-5x+1\)) + x ( \(x^2+11\))
d) (x - 3y ) \(\left(x^2+3xy+9y^2\right)\)
e) \(\left(3+x\right)\left(x^2+3x-5\right)\)
f) (x+2)(x-2)-(2x+1)
2. Rút gọn biểu thức
a ) \(\left(3x+2\right)^2+2\left(2+3x\right)\left(1-2y\right)+\left(2y-1\right)^2\)
b ) \(\left(3x+1\right)^2-2\left(3x+1\right)\left(3x+5\right)+\left(3x+5\right)^2\)
c) \(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)
Tính
a, \(\frac{1}{\left(y-1\right)\left(y-2\right)}+\frac{2}{\left(2-y\right)\left(3y-y\right)}+\frac{3}{\left(1-y\right)\left(y-3\right)}\)
b, \(\frac{x^2}{x+1}+\frac{2x}{x^2-1}-\frac{1}{1-x}+1\)
c, \(\frac{1}{x^2+3x+2}-\frac{2x}{x^2+4x^2+4x}+\frac{1}{x^2+5x+6}\)
\(a,\frac{3x^2-6xy+3y^2}{5x^2-5xy+5y^2}:\frac{10x-10y}{x^3+y^3}\)
\(b,(\frac{x+2}{x+1}-\frac{2x}{x-1}).\frac{3x+3}{x}+\frac{4x^2+x+7}{x^2-x}\)
\(c,\frac{2}{xy}:\left(\frac{1}{x}-\frac{1}{y}\right)-\frac{x^2-y^2}{\left(x-y\right)^2}\)
\(d,\frac{\frac{x-y}{x+y}-\frac{x+y}{x-y}}{1-\frac{x^2}{x^2+y^2}}\)
\(e,\left(\frac{1}{x+1}-\frac{3}{x^3+1}+\frac{3}{x^2-x+1}\right).\frac{3x^2-3x+3}{\left(x+1\right)\left(x+2\right)}+\frac{2x-2}{x^2+2x}\)
Thực hiện phép tính:
\(a.\left(x+1\right)\left(2x-3\right)+\left(x+2\right)^2-3x^2-3x\)
\(b.\left(x^2+2x-3\right):\left(x+1\right)+x^2-3x-2\)
\(c.\frac{1}{xy-x^2}-\frac{1}{y^2-xy}\)
\(d.\frac{x-1}{x^2-5x+4}-\frac{4}{x^2-4x}\)
Rút gọn biểu thức rồi tính giá trị:
a) \(\frac{x^2y\left(y-x\right)+xy^2\left(x-y\right)}{3y^2-3x^2}\) ,với x = -3 ; y =\(\frac{1}{2}\)
b) \(\frac{\left(8x^3-y^3\right)\left(4x^2-y^2\right)}{\left(2x+y\right)\left(4x^2-4xy+y^2\right)}\)với x = 2; y =\(\frac{-1}{2}\)
\(B=\left[\left(\frac{x}{y}-\frac{y}{x}\right):\left(x-y\right)-2\left(\frac{1}{y}-\frac{1}{x}\right)\right]:\frac{x-y}{y}\)
\(C=\left(\frac{x+y}{2x-2y}-\frac{x-y}{2x+2y}-\frac{2y^2}{y-x}\right):\frac{2y}{x-y}\)
\(D=3x:\left\{\frac{x^2-y^2}{x^3+y^3}\left[\left(x-\frac{x^2+y^2}{y}\right):\left(\frac{1}{x}-\frac{1}{y}\right)\right]\right\}\)
\(E=\frac{2}{x\left(x+1\right)}+\frac{2}{\left(x+1\right)\left(x+2\right)}+\frac{2}{\left(x+2\right)\left(x+3\right)}\)