a) \(\dfrac{2}{3}x-\dfrac{2}{3}=\dfrac{7}{12}-1\Leftrightarrow\dfrac{2}{3}x=\dfrac{7}{12}-1+\dfrac{2}{3}=\dfrac{1}{4}\Leftrightarrow x=\dfrac{3}{8}\)
b)\(\dfrac{1}{2}x+\dfrac{3}{5}\left(x-2\right)=3\Leftrightarrow\dfrac{1}{2}x+\dfrac{3}{5}x-\dfrac{6}{5}=3\Leftrightarrow\dfrac{11}{10}x=\dfrac{21}{5}\Leftrightarrow x=\dfrac{42}{11}\)
c)
\(\dfrac{3}{4}\left|x+5\right|+\dfrac{7}{8}=1\dfrac{1}{6}\Leftrightarrow\dfrac{3}{4}\left|x+5\right|=\dfrac{7}{6}-\dfrac{7}{8}=\dfrac{7}{24}\Leftrightarrow\left|x+5\right|=\dfrac{7}{18}\Leftrightarrow\left[{}\begin{matrix}x+5=\dfrac{7}{18}\\x+5=-\dfrac{7}{18}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{83}{18}\\x=-\dfrac{97}{18}\end{matrix}\right.\)
a) 12x+35(x−2)=3⇔12x+35x−65=3⇔1110x=215⇔x=421112x+35(x−2)=3⇔12x+35x−65=3⇔1110x=215⇔x=4211
c)