Question

Làm giúp mình với

Answer 1

\(\left(x+\dfrac{1}{2}\right)^2-\dfrac{49}{36}=0\)

\(\left(x+\dfrac{1}{2}\right)^2\)           \(=0+\dfrac{49}{36}=\perp\left(\dfrac{7}{6}\right)^2\)

\(\text{Vậy }x+\dfrac{1}{2}=\dfrac{7}{6}\)

       \(x\)         \(=\dfrac{7}{6}+\left(\dfrac{-1}{2}\right)=\dfrac{2}{3}\)

\(\text{hoặc }x+\dfrac{1}{2}=\left(\dfrac{-7}{6}\right)\)

        \(x\)          \(=\left(\dfrac{-7}{6}\right)+\left(\dfrac{-1}{2}\right)=\dfrac{-5}{3}\)

\(\Rightarrow x\in\left\{\dfrac{2}{3};\left(\dfrac{-5}{3}\right)\right\}\)

Answer 2

(x+1/2)^2-49/36=0
(x+1/2)^2=0+49/36
(x+1/2)^2=49/36
(x+1/2)^2=(+-7/6)^2
x+1/2=7/6 hoặc x+1/2=(-7/6)
=>x=2/3 hoặc x=-5/3