\(a,Ca+2HCl\rightarrow CaCl_2+H_2\left(1\right)\\ CaO+2HCl\rightarrow CaCl_2+H_2O\left(2\right)\\ Đặt:n_{Ca}=a\left(mol\right);n_{CaO}=b\left(mol\right)\\ \Rightarrow\left\{{}\begin{matrix}111a+111b=22,2\\22,4a=2,24\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=0,1\\b=0,1\end{matrix}\right.\\ \Rightarrow\%m_{CaO}=\dfrac{0,1.56}{0,1.56+0,1.40}.100\approx52,83\%\\ \Rightarrow\%m_{Ca}=47,17\%\\ b,n_{HCl}=2.\left(a+b\right)=0,4\left(mol\right)\\ \Rightarrow m_{ddHCl}=\dfrac{0,4.36,5.100}{36,5}=40\left(g\right)\)
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