\(1,\\ f\left(0\right)=0-0-3=-3;f\left(1\right)=1-2-3=-4\\ f\left(-1\right)=1+2-3=0;f\left(2\right)=4-4-3=-3\\ f\left(-2\right)=4+4-3=5;f\left(3\right)=9-6-3=0\\ f\left(-3\right)=9+6-3=12;f\left(\dfrac{1}{2}\right)=\dfrac{1}{4}-1-3=-\dfrac{15}{4}\\ f\left(-\dfrac{1}{2}\right)=\dfrac{1}{4}+1-3=-\dfrac{7}{4}\)