\(a,\frac{2x+1}{x-1}=\frac{5\left(x-1\right)}{x+1}\)
\(ĐK:x\ne\pm1\)
\(PT\Leftrightarrow\left(2x+1\right)\left(x-1\right)=5\left(x-1\right)^2\)
\(\Leftrightarrow2x^2-x-1=5\left(x^2-2x+1\right)\)
\(\Leftrightarrow3x^2-9x+4=0\)
\(\Leftrightarrow3\left(x^2-2.\frac{3}{2}x+\frac{9}{4}\right)=\frac{11}{4}\)
\(\Leftrightarrow\left(x-\frac{3}{2}\right)^2=\frac{11}{12}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\sqrt{\frac{11}{12}}+\frac{3}{2}\\x=-\sqrt{\frac{11}{12}}+\frac{3}{2}\end{cases}}\)
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