theo ket qua cho thay:9.4594<10
Ta có :
\(\sqrt{3}< \sqrt{4}=2\)
\(\sqrt{8}< \sqrt{9}=3\)
\(\sqrt{24}< \sqrt{25}=5\)
\(\Rightarrow\sqrt{3}+\sqrt{8}+\sqrt{24}< 2+3+5=10\)(đpcm)
Vậy ...
\(\sqrt{3}+\sqrt{8}+\sqrt{24}< \sqrt{4}+\sqrt{9}+\sqrt{25}\)
\(=2+3+5=10\)
Vậy: \(\sqrt{3}+\sqrt{8}+\sqrt{24}< 10\)
Ta thấy :
\(\sqrt{3}< \sqrt{4}\)
\(\sqrt{8}< \sqrt{9}\)
\(\sqrt{24}< \sqrt{25}\)
Do đó :<
\(\sqrt{3}+\sqrt{8}+\sqrt{24}\)<\(\sqrt{4}+\sqrt{9}+\sqrt{25}=2+3+5=10\)
Vậy : . .
H OK TỐT
