\(B=2004\times2008\)
\(B=\left(2007-3\right)\times\left(2007+1\right)\)
\(B=\left(2007-3\right)\times2007+\left(2007-3\right)\)
\(B=2007\times2007-3\times2007+2007-3\)
\(B=2007\times2007-3\times2007+2004\)\(>2007\times2007=A\)
Vậy B > A
_Hok tốt_
!!!
a)\(A=2007\times2007\)
\(A=2004\times2007+3\times2007\)
b) \(B=2004\times2008\)
\(B=2004\times\left(2007+1\right)\)
\(B=2004\times2007+2004\)
Vì 2004 x 2007 = 2004 x 2007 và 3 x 2007 > 2004 nên A > B
ta có B=2004*2008=(2007-3)*(2007+1)=2007*2007-2*2007-3
suy ra A>B
xin
À mik nhầm
\(B=2007\times2007-3\times2007+2004< 2007\times2007=A\)
\(\Rightarrow B< A\)
Sorry rất nhìu T^T
+) A = 2007 x 2007
A = 2007 x ( 2004 + 3 )
A = 2007 x 2004 + 2007 x 3
A = 2007 x 2004 + 6021
+) B = 2004 x 2008
B = 2004 x ( 2007 + 1 )
B = 2004 x 2007 + 2004 x 1
B = 2004 x 2007 + 8016
A = 2004 x 2007 + 6021 , B = 2004 x 2007 + 8016
Ta thấy : A = 2004 x 2007 = B =2004 x 2007
Nên ta có : 6021 < 8016
=> A < B
Ta có : A = (2004 + 3) × (2004 + 3)
B= (2004 + 0 )× (2004 + 4)
===> A>B
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