Ta có :
A=2017.2017=(2016+1)2017
A=2017.2016+2017
Ta lại có :
B=2016.2018=2016(2017+1)
B=2016.2017+2016
Mà 2017>2016
\(\Rightarrow\)2017.2016+2017>2017.2016+2016
\(\Rightarrow\)A>B
B = 2016 x 2018
= (2017-1)(2017+1)
= 2017x2017 + 2017 - 2017 - 1
= 2017x2017 -1
Vậy A > B
Ta có :
A=2017.2017=(2016+1)2017
A=2017.2016+2017
Ta lại có :
B=2016.2018=2016(2017+1)
B=2016.2017+2016
Mà 2017>2016
⇒2017.2016+2017>2017.2016+2016
⇒A>B