Ta có:\(\frac{12}{48}=\frac{1}{4}\) \(\frac{9}{36}\)= \(\frac{1}{4}\)
Vì\(\frac{1}{4}=\frac{1}{4}\)nên \(\frac{12}{48}=\frac{9}{36}\)
Vậy \(\frac{12}{48}=\frac{9}{36}\)
khong quy dong mau so hay so sanh;
A= \(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}};\) B= \(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
so sanh -17/23 va -25/31 khong can quy dong
A=2000/2001 + 2001/2000 ; B=2000/2001+2001/2002
khong quy dong. So sanh A va B
So sanh khong qua quy dong: A = \(\frac{-7}{10^{2005}}\)+ \(\frac{-15}{10^{2006}}\); B = \(\frac{-15}{10^{2005}}\)+ \(\frac{-7}{10^{2006}}\)
Khong dung may tinh bo tui .Rut gon roi quy dong cac phan so sau
a)\(\frac{17}{20},\frac{13}{15}va\frac{41}{60}\)
b)\(\frac{25}{75},\frac{17}{34}va\frac{121}{132}\)
KO QUY DONG MAU HAY SO SANH
\(A=\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
ko quy dong mau so hay so sanh: A=-9/10^2015+-19/10^2016 va -9/10^2016+-19/10^2015
Cac ban giup may.khong quy dong so sanh;A=-9/10^2010+-9/10^2011 va B=-9/10^2011+-19/10^2010
khong quy dong hay so sanh
A=-9/102010+-19/102011 ; B-9/102011+ -19/102010
