A= 1+\(\frac{1}{3}+\frac{1}{9}+\frac{1}{27} +\frac{1}{81}\)
=1+\(\frac{1}{3^1}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}\)
=> 3A-A=(\(\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3}+1\))-(1+\(\frac{1}{3^1}+\frac{1}{3^2}+\frac{1}{3^3}+\frac{1}{3^4}\))
=>2A=3-\(\frac{1}{3^4}\)
=> A=(3-\(\frac{1}{3^4}\)):2
dùng casio đi bạn , ra ngay ý mà !!
toán lớp 5 thì sao làm như vậy đc !!