Question

Không quy đồng mẫu số hãy so sánh \(A=\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)\(;B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)

Answer 1

\(A-B=\frac{10}{10^{2010}}-\frac{10}{10^{2011}}=\frac{1}{10^{2009}}-\frac{1}{10^{2010}}>0\)

\(\Rightarrow A>B\)

Answer 2

Answer 3

+)Ta có:A=\(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}=\frac{-9}{10^{2010}}+\frac{-9}{10^{2011}}+\frac{-10}{10^{2011}}\)

+)Ta lại có:B=\(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}=\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}+\frac{-10}{10^{2010}}\)

+)Ta thấy:\(\frac{-10}{10^{2011}}>\frac{-10}{10^{2010}}\)

=>\(\frac{-9}{10^{2010}}+\frac{-9}{10^{2011}}+\frac{-10}{10^{2011}}\)>\(\frac{-9}{10^{2011}}+\frac{-9}{10^{2010}}+\frac{-10}{10^{2010}}\)

Hay A>B

Vậy A>B

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