Question

Không quy đồng , hãy tính hợp lí tổng sau

C = \(\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\) .     \(\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)​​

Answer 1

Ta thay 1/2 - 1/3 - 1/6 = 0 ma khi 1 thua so nao nhan voi 0 thi h se la 0 

Vay C= 0

Answer 2

h la h nha mk an nham

Answer 3

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\cdot\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).0=0\)

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Answer 4

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right).\)

   \(=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).\left(\frac{1}{6}-\frac{1}{6}\right)\)

   \(=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).0\)

     \(=0\)

Answer 5

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(\Rightarrow C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).0\)

\(\Rightarrow C=0\)

Answer 6

\(C=\left(\frac{12}{199}+\frac{23}{200}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(C=\left(\frac{12}{199}+\frac{23}{200}\right).\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)

\(C=\left(\frac{12}{199}+\frac{23}{200}\right).0\)

\(C=0\)

Answer 7

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\cdot\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\cdot\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)

\(C=\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right)\cdot0\)

\(C=0\)