a) Ta có:
a = 1002.1001
a = 1002.( 1000 + 1 )
a = 1002.1000 + 1002
b = 1003.1000
b = ( 1002 + 1 ).1000
b = 1002.1000 + 1000
Vậy a = 1002.1000 + 1002
b = 1002.1000 + 1000
=> a > b
b) Ta có:
a = 2002.2002
a = 2002. ( 2000 + 2 )
a = 2002.2000 + 2002.2
a = 2002.2000 + 4004
b = 2000.2004
b = 2000. ( 2002 + 2 )
b = 2000.2002 + 2000.2
b = 2000.2002 + 4000
Vậy a = 2002.2000 + 4004
b = 2000.2002 + 4000
=> a > b
c) Ta có:
a = 2016.2016
a = 2016.( 2014 + 2 )
a = 2016.2014 + 2016.2
b = 2014.2015
b = 2014. ( 2016 - 1 )
b = 2014.2016 - 2014
Vậy a = 2016.2014 + 2016.2
b = 2014.2016 - 2014
=> a > b