Gọi số đã cho là A.Ta có:
A = 4a + 3
= 17b + 9 (a,b,c thuộc N)
= 19c + 3
Mặt khác: A + 25 = 4a+3+25=4a+28=4(a+7)
=17b+9+25=17b+34=17(b+2)
=19c+13+25=19c+38=19(c+2)
Như vậy A+25 đồng thời chia hết cho 4,17,19.Mà (4;17;19)=1=>A+25 chia hết cho 1292.
=>A+25=1292k(k=1,2,3,....)=>A=1292k-25=1292k-1292+1267=1292(k-1)+1267.
Do 1267<1292 nên 1267 là số dư trong phép chia số đã cho A cho 1292.
A= 4p+3 = 17m+9= 19n+13 A+25 =4p+28= 17m+34 =19n+38 nhận thấy A+25 đồng thời chia hết cho 4, 17 và 19 vậy A+25 chia hết cho 4.17.19 =1292 A chia 1292 dư (1292-25) = 1267
1267 đúng 100% mình cũng làm mà violympic đúng ko
mình vừa làm violympic xong 1267 chuẩn 100% luôn
mik vừa làm ở violympic xong đs là 1292 đó
đúng 1000000000000000000% luôn đó nha
rốt cuộc là bao nhiêu hả ????????????????????????????????????????????????????????
Nhiều đáp án thế này bt chọn cái nào bây giờ
tôi chắc chấn là 1267 lun đó 10000000000000000000000000000000000000000 phần trăm lun vừa thi violympic vòng 9 xong đc 100 điểm nè
1276 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%
số dư là 1292 sao được , 1267 mới đúng, k đọc đề à
mik vừa làm câu hỏi của cpvm đáp số 1267 đó đúng 100000000000000000000000000000000000000000000000000000000000000000000000000%
ngu 1292 = 1292(so du bang so chia ) thi so du = 0 r
1292 đúng luôn tôi thi học sinh giỏi 6 có trong đề
A= 4p+3 = 17m+9= 19n+13
A+25 =4p+28= 17m+34 =19n+38
nhận thấy A+25 đồng thời chia hết cho 4, 17 và 19
vậy A+25 chia hết cho 4.17.19 =1292
A chia 1292 dư (1292-25) = 1267
làl1267 dó
10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%